Observation : From TDB1 : T1 {; T2 < a1, …, a100>} We get a frequent i translation - Observation : From TDB1 : T1 {; T2 < a1, …, a100>} We get a frequent i Indonesian how to say

Observation : From TDB1 : T1 {; T2

Observation : From TDB1 : T1 {; T2 < a1, …, a100>}
We get a frequent itemsets: (a1, …, a50)
Also, it subsets are all frequent: (a1),(a1),.., (a50),(a1,..,a49),....
There must be some hidden relationships among frequent patterns!
The downward closure (also called “Apriori) property of frequent patterns
If {beer, diaper, nuts} is frequent, so is {beer, diaper}
Every transaction containing {beer, diaper, nuts} also contains {beer, diaper}
Apriori: Any subset of a frequent itemset must be frequent
Efficient mining methodology
If any subset if an itemset S is infrequent, then there is no chance for S to be frequent – why do we even have to consider S?
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Results (Indonesian) 1: [Copy]
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Pengamatan: Dari TDB1: T1 {; T2 < a1,..., a100 >} Kita mendapatkan itemsets sering: (a1,..., a50)Juga, itu subset semua sering: (a1),(a1),.., (a50),(a1,..,a49),... Harus ada beberapa hubungan yang tersembunyi di antara pola-pola yang sering!Properti ke bawah penutupan (juga disebut "Apriori) sering polaJika {bir, popok, kacang-kacangan} sering, jadi {bir, popok}Setiap transaksi yang mengandung {bir, popok, kacang-kacangan} juga berisi {bir, popok}Apriori: Himpunan bagian dari itemset sering harus seringMetodologi efisien pertambanganJika bagian jika itemset S jarang, maka tidak ada kesempatan bagi S harus sering-mengapa kita bahkan harus mempertimbangkan S?
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Results (Indonesian) 2:[Copy]
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Pengamatan: Dari TDB1: T1 {; T2 <a1, ..., a100>}
Kami mendapatkan itemset sering: (a1, ..., a50)
Selain itu, subset semua sering: (a1), (a1), .., (a50), (a1, .. , A49), ....
pasti ada hubungan tersembunyi antara pola yang sering!
penutupan bawah (juga disebut "Apriori) milik pola yang sering
Jika {bir, popok, kacang} sering, jadi {bir, popok}
Setiap transaksi yang mengandung {bir, popok, kacang} juga mengandung {bir, popok}
Apriori: setiap bagian dari frequent itemset harus sering
metodologi pertambangan Efisien
Jika subset jika itemset S jarang terjadi, maka tidak ada kesempatan untuk S menjadi sering - mengapa bahkan kita harus mempertimbangkan S?
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