Theorem 1. Let A be a n × n matrix, and let p(λ) = det(λI − A) be the  translation - Theorem 1. Let A be a n × n matrix, and let p(λ) = det(λI − A) be the  Thai how to say

Theorem 1. Let A be a n × n matrix,

Theorem 1. Let A be a n × n matrix, and let p(λ) = det(λI − A) be the characteristic polynomial of A. Then p(A) = 0.
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Results (Thai) 1: [Copy]
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ทฤษฎีบทที่ 1 ให้ A เป็นเมทริกซ์ n n × และให้ p(λ) =เดช (λI − A) เป็นพหุนามลักษณะของ แล้ว p(A) = 0
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Results (Thai) 2:[Copy]
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ทฤษฎีบท 1. ให้เป็น× n เมทริกซ์และให้ P (λ) = เดชอุดม (λI -) เป็นพหุนามลักษณะของ A. แล้ว P (A) = 0
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Results (Thai) 3:[Copy]
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ทฤษฎีบทที่ 1 ปล่อยให้เป็น n × n เมทริกซ์ให้ P ( λ ) = เดช ( λผม− ) เป็นพหุนามลักษณะเฉพาะของ แล้ว P ( A ) = 0
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